y=1/2x^2+2x-3

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Solution for y=1/2x^2+2x-3 equation:


x in (-oo:+oo)

y = (1/2)*x^2+2*x-3 // - (1/2)*x^2+2*x-3

y-((1/2)*x^2)-(2*x)+3 = 0

(-1/2)*x^2-2*x+y+3 = 0

y-1/2*x^2-2*x+3 = 0

DELTA = (-2)^2-(-1/2*4*(y+3))

DELTA = 2*(y+3)+4

2*(y+3)+4 = 0

2*(y+3)+4 = 0

2*y+10 = 0

2*y+10 = 0

2*y+10 = 0 // - 10

2*y = -10 // : 2

y = -10/2

y = -5

DELTA = 0 <=> t_1 = -5

x = 2/(-1/2*2) i y = -5

x = -2 i y = -5

( x = ((2*(y+3)+4)^(1/2)+2)/(-1/2*2) or x = (2-(2*(y+3)+4)^(1/2))/(-1/2*2) ) i y > -5

( x = -((2*(y+3)+4)^(1/2)+2) or x = (2*(y+3)+4)^(1/2)-2 ) i y > -5

y+5 > 0

y+5 > 0 // - 5

y > -5

x in { -2, -((2*(y+3)+4)^(1/2)+2), (2*(y+3)+4)^(1/2)-2 }

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